min() -- return the smaller of its two arguments

print min(a,b) 

Return the minimum of its two argument.

dim m(10) 
for a=1 to 1000 
	m=min(ran(10),ran(10)) 
	m(m)=m(m)+1 
next a 

for a=1 to 9 
	print a,": ",m(a) 
next a 

  For each iteration of the loop, the lower of two random number is recorded. The result is printed at the end.